MultiplicationPrinciple AMC8 Basic
2014


Problem - 3369

The "Middle School Eight" basketball conference has $8$ teams. Every season, each team plays every other conference team twice (home and away), and each team also plays $4$ games against non-conference opponents. What is the total number of games in a season involving the "Middle School Eight" teams?


Among conferencing teams, there are totally $8\times 7=56$ games. This is because the home team has $8$ choices and have $7$ teams to choose from as its opponent.

Additionally, there are $8\times 4=32$ games. Therefore the answer is $$56+32=\boxed{88}$$

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