CeilingAndFloor 华杯 Basic
2015

Problem - 2666
How many solutions does the following system have? $$\left\{ \begin{array}{ll} \lfloor x \rfloor + 2y &= 1\\ \lfloor y \rfloor + x &=2 \end{array} \right.$$ Where $\lfloor x \rfloor$ and $\lfloor y \rfloor$ denote the largest integers not exceeding $x$ and $y$, respectively.

The solution for this problem is available for $0.99. You can also purchase a pass for all available solutions for$99.