MultiplicationPrinciple AMC8 Basic
2015


Problem - 2567

How many integers between $1000$ and $9999$ have four distinct digits?


By the multiplication principle, the answer is $$9\times 9\times 8\times 7 = \boxed{4536}$$

This is because the thousands digit has $9$ choices (excluding $0$), the hundreds, tens and ones digit have $9$, $8$, and $7$ choices, respectively.

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