MultiplicationPrinciple NumberTheoryBasic Basic

Problem - 2481

How many positive divisors does $20$ have?


Answer     $6$

As the prime factorization of $20$ is $2^2\times 5$. There are three ways to pick up $2$, including no $2$ is chosen. Similarly, there are $2$ ways to pick up $5$. Hence the result is $3\times 2=\boxed{6}$.

In a more concise way, because $20=2^2\times 5$, we find the answer is $(2+1)\times(1+1)=6$.

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