BinomialExpansion Basic

Problem - 2711

Find the coefficient of the $x$ term after having expanded $$(x^2+3x+2)^5$$


Answer     $240$

Because $$(x^2+3x+2)^5=(x+1)^5(x+2)^5=(\cdots + 5x + 1)(\cdots + 5\cdot 2^4 x + 2^5)$$

therefore the answer is $$5\times 2^5 + 1\times 5\times 2^4=\boxed{240}$$

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